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e^ix = isin(x) + cos(x)

SCscratchfan321•Created March 19, 2023
e^ix = isin(x) + cos(x)
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Instructions

This is a pure math project with an argand diagram to show the formula: e^ix = isin(x) + cos(x) This project shows that the two operations are the same. From this, it is clear that e ^ (i * pi) = -1. The red cross uses cos and sin with the angle. The blue cross uses exponents with complex numbers to solve e^(i * angle) #pi #maths #math

Project Details

Project ID821839173
CreatedMarch 19, 2023
Last ModifiedMarch 19, 2023
SharedMarch 19, 2023
Visibilityvisible
CommentsAllowed