TURBO MODE (+ FULL SCREEN for faster) 30 Ago 2015
Zn+1 = Zn^k + c I wanted to try Julia Sets for Z^k with k> 2. But it seemed me that k> 4 don't work on Scratch, perhaps because it requires a large number of iterations? (may be it results with lists and compressing them previously ?) Music: Shubert Serenade (YouTube)
