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Newton's fractal f(z) =z^-6+1 F(z)=z^-5/-5-z

LEleszpio•Created February 4, 2022
Newton's fractal f(z) =z^-6+1 F(z)=z^-5/-5-z
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Newton’s method(2) f(z+1) = f(z) - F(z)/f (z) f(z) =z^-6+1 F(z)=F(z)=z^-5/-5-z F'(z)=f(z) F is the integral of f

Project Details

Project ID639211996
CreatedFebruary 4, 2022
Last ModifiedFebruary 9, 2022
SharedFebruary 4, 2022
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