Generalized Newton's fractal f(z) =z^-6+i F(z)=z^-5/-5-iz a=1-i

LEleszpio•Created February 3, 2022

$Generalized Newton's fractal f(z) =z^-6+i F(z)=z^-5/-5-iz a=1-i$

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Generalized Newton’s method(2) f(z+1) = f(z) - a* F(z)/f (z) f(z) =z^-6+i where a=1-i F(z)=z^-5/-5-iz F'(z)=f(z) F is the integral of f

Project ID638423472

CreatedFebruary 3, 2022

Last ModifiedFebruary 13, 2022

SharedFebruary 13, 2022

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