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Newton's fractal f(z) =z^-5-i F(z)=z^-4/-4-iz

LEleszpio•Created January 20, 2022
Newton's fractal f(z) =z^-5-i F(z)=z^-4/-4-iz
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Newton’s method(2) f(z+1) = f(z) - F(z)/f (z) f(z) =z^-5-i F(z)=F(z)=z^-4/-4-iz F'(z)=f(z) F is the integral of f

Project Details

Project ID631076906
CreatedJanuary 20, 2022
Last ModifiedFebruary 3, 2022
SharedJanuary 20, 2022
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