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Newton's fractal f(z) =z^8+1 F(z)=z^9/9+z

LEleszpio•Created January 16, 2022
Newton's fractal f(z) =z^8+1 F(z)=z^9/9+z
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Newton’s method(2) f(z+1) = f(z) - F(z)/f (z) f(z) =z^8+1 F(z)=z^9+z/9 F'(z)=f(z) F is the integral of f

Project Details

Project ID629151621
CreatedJanuary 16, 2022
Last ModifiedFebruary 12, 2022
SharedJanuary 16, 2022
Visibilityvisible
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