Newton's fractal f(z) =z^-3-1-i

LEleszpio•Created January 14, 2022

$Newton's fractal f(z) =z^-3-1-i$

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Newton’s method f(z+1) = f(z) - f(z)/f '(z) f(z)=z^-3-1-i f '(z)=-3z^-4

Project ID628437148

CreatedJanuary 14, 2022

Last ModifiedJanuary 17, 2022

SharedJanuary 14, 2022

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