Newton's fractal f(z) =z^-2-1

LEleszpio•Created January 13, 2022

$Newton's fractal f(z) =z^-2-1$

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Newton’s method f(z+1) = f(z) - f(z)/f '(z) f(z)=z^-2-1 f '(z)=-2z^-3

Project ID627834999

CreatedJanuary 13, 2022

Last ModifiedJanuary 15, 2022

SharedJanuary 13, 2022

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