Newton's fractal f(z) =z^-1+0.71+0.71i

LEleszpio•Created January 12, 2022

$Newton's fractal f(z) =z^-1+0.71+0.71i$

91 views

Instructions

Turbo Mode

Newton’s method f(z+1) = f(z) - f(z)/f '(z) f(z)=z^-1+0.71+0.71i f '(z)=-z^-2

Project ID627258794

CreatedJanuary 12, 2022

Last ModifiedFebruary 17, 2022

SharedJanuary 12, 2022

Visibilityvisible

CommentsAllowed