Newton's fractal f(z) =z^6-1

LEleszpio•Created December 19, 2021

$Newton's fractal f(z) =z^6-1$

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Newton’s method f(z+1) = f(z) - f(z)/f '(z) f(z)=z^6-1 f '(z)=6z^5

Project ID619230163

CreatedDecember 19, 2021

Last ModifiedJanuary 21, 2022

SharedDecember 19, 2021

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