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Julia Set Z^12/|Z|^8+c(c=0.8-0.342i)

LEleszpio•Created September 14, 2019
Julia Set Z^12/|Z|^8+c(c=0.8-0.342i)
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Description

Z=x+iy Z=|Z|(cosα + i sinα) where |Z|=sqrt(x^2+y^2) α=arctg(y/x) To calculate the power of complex numbers, I used the de Moivre formula. Z^12+c=(|Z|^12)*(cos(12*α) + i sin(12*α))+c c=0.8555+0.1122i

Project Details

Project ID328961390
CreatedSeptember 14, 2019
Last ModifiedNovember 28, 2019
SharedNovember 28, 2019
Visibilityvisible
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