Julia Set Z^10/|Z|^6+c(c=-0.888+0.11i)

LEleszpio•Created September 7, 2019

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Z=x+iy Z=|Z|(cosα + i sinα) where |Z|=sqrt(x^2+y^2) α=arctg(y/x) To calculate the power of complex numbers, I used the de Moivre formula. Z^10+c=(|Z|^10)*(cos(10*α) + i sin(10*α))+c c=-0.888+0.11i

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Project ID327517948

CreatedSeptember 7, 2019

Last ModifiedNovember 27, 2019

SharedNovember 27, 2019

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