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Julia Set Z^12+ZC

LEleszpio•Created August 10, 2019
Julia Set Z^12+ZC
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Instructions

C=ZR+ZIi Green Flag Enter the value of ZR (from 0.8 to 1.3) Enter the value of ZI (from 0.7 to 1.2)

Description

Z=x+iy Z=|Z|(cosα + i sinα) where |Z|=sqrt(x^2+y^2) α=arctg(y/x) To calculate the power of complex numbers, I used the de Moivre formula. Z^12+ZC=(Z^11+C)*Z Z^12+ZC=((|Z|^11)*(cos(11*α) + i sin(11*α))+c)*(x+yi) C=ZR+ZIi

Project Details

Project ID323802667
CreatedAugust 10, 2019
Last ModifiedSeptember 25, 2019
SharedSeptember 25, 2019
Visibilityvisible
CommentsAllowed

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