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Julia Set Z^-10+c(c=-1.1516)

LEleszpio•Created July 20, 2019
Julia Set Z^-10+c(c=-1.1516)
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Z=x+iy Z=|Z|(cosα + i sinα) where |Z|=sqrt(x^2+y^2) α=arctg(y/x) To calculate the power of complex numbers, I used the de Moivre formula. Z^-10+c=(|Z|^-10)*(cos(-10*α) + i sin(-10*α))+c c=-1.1516

Project Details

Project ID321710029
CreatedJuly 20, 2019
Last ModifiedJanuary 31, 2021
SharedJanuary 31, 2021
Visibilityvisible
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