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Julia Set Z^10+c(c=-0.8876+0.102i)

LEleszpio•Created July 11, 2019
Julia Set Z^10+c(c=-0.8876+0.102i)
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Z=x+iy Z=|Z|(cosα + i sinα) where |Z|=sqrt(x^2+y^2) α=arctg(y/x) To calculate the power of complex numbers, I used the de Moivre formula. Z^10+c=(|Z|^10)*(cos(10*α) + i sin(10*α))+c c=-0.8876+0.102i

Project Details

Project ID320620400
CreatedJuly 11, 2019
Last ModifiedSeptember 7, 2019
SharedSeptember 7, 2019
Visibilityvisible
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